Cartesian morphisms #
This file defines cartesian resp. strongly cartesian morphisms in a based category.
Main definitions #
IsCartesian p f φ expresses that φ is a cartesian arrow lying over f with respect to p in
the sense of SGA 1 VI 5.1. This means that for any morphism φ' : a' ⟶ b lying over f there is
a unique morphism τ : a' ⟶ a lying over 𝟙 R, such that φ' = τ ≫ φ.
References #
The proposition that a morphism φ : a ⟶ b in 𝒳 lying over f : R ⟶ S in 𝒮 is a
cartesian arrow, see SGA 1 VI 5.1.
- cond : CategoryTheory.IsHomLiftAux p f φ
- universal_property : ∀ {a' : 𝒳} (φ' : a' ⟶ b) [inst : p.IsHomLift f φ'], ∃! χ : a' ⟶ a, p.IsHomLift (CategoryTheory.CategoryStruct.id R) χ ∧ CategoryTheory.CategoryStruct.comp χ φ = φ'
Instances
Given a cartesian arrow φ : a ⟶ b lying over f : R ⟶ S in 𝒳, a morphism φ' : a' ⟶ b
lifting 𝟙 R, then IsCartesian.map f φ φ' is the morphism a' ⟶ a obtained from the universal
property of φ.
Equations
Instances For
Equations
- ⋯ = ⋯
Given a cartesian arrow φ : a ⟶ b lying over f : R ⟶ S in 𝒳, a morphism φ' : a' ⟶ b
lifting 𝟙 R, and a morphism ψ : a' ⟶ a such that g ≫ ψ = φ'. Then ψ is the map induced
by the universal property of φ.
Given a cartesian arrow φ : a ⟶ b lying over f : R ⟶ S in 𝒳, a morphism φ' : a' ⟶ b
lifting 𝟙 R, and two morphisms ψ ψ' : a' ⟶ a such that g ≫ ψ = φ' = g ≫ ψ'. Then we must
have ψ = ψ'.
The canonical isomorphism between the domains of two cartesian arrows lying over the same object.
Equations
- One or more equations did not get rendered due to their size.
Instances For
Precomposing a cartesian morphism with an isomorphism lifting the identity is cartesian.
Equations
- ⋯ = ⋯
Postcomposing a cartesian morphism with an isomorphism lifting the identity is cartesian.
Equations
- ⋯ = ⋯