Exposed sets #
This file defines exposed sets and exposed points for sets in a real vector space.
An exposed subset of A is a subset of A that is the set of all maximal points of a functional
(a continuous linear map E β π) over A. By convention, β
is an exposed subset of all sets.
This allows for better functoriality of the definition (the intersection of two exposed subsets is
exposed, faces of a polytope form a bounded lattice).
This is an analytic notion of "being on the side of". It is stronger than being extreme (see
IsExposed.isExtreme), but weaker (for exposed points) than being a vertex.
An exposed set of A is sometimes called a "face of A", but we decided to reserve this
terminology to the more specific notion of a face of a polytope (sometimes hopefully soon out
on mathlib!).
Main declarations #
IsExposed π A B: States thatBis an exposed set ofA(in the literature,Ais often implicit).IsExposed.isExtreme: An exposed set is also extreme.
References #
See chapter 8 of [Barry Simon, Convexity][simon2011]
TODO #
Define intrinsic frontier/interior and prove the lemmas related to exposed sets and points.
Generalise to Locally Convex Topological Vector Spacesβ’
More not-yet-PRed stuff is available on the branch sperner_again.
A set B is exposed with respect to A iff it maximizes some functional over A (and contains
all points maximizing it). Written IsExposed π A B.
Equations
Instances For
A useful way to build exposed sets from intersecting A with halfspaces (modelled by an
inequality with a functional).
Instances For
IsExposed is not transitive: Consider a (topologically) open cube with vertices
Aβββ, ..., Aβββ and add to it the triangle AβββAβββAβββ. Then AβββAβββ is an exposed subset
of AβββAβββAβββ which is an exposed subset of the cube, but AβββAβββ is not itself an exposed
subset of the cube.
If B is a nonempty exposed subset of A, then B is the intersection of A with some closed
halfspace. The converse is not true. It would require that the corresponding open halfspace
doesn't intersect A.
For nontrivial π, if B is an exposed subset of A, then B is the intersection of A with
some closed halfspace. The converse is not true. It would require that the corresponding open
halfspace doesn't intersect A.
A point is exposed with respect to A iff there exists a hyperplane whose intersection with
A is exactly that point.
Equations
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Exposed points exactly correspond to exposed singletons.