Blueprint for the collaborative Formalization Seminar

4 Distributions

Laurent Schwartz introduced the notion of distributions two talk about generalized solutions to differential equations. For his work he got the fields medal.

4.1 Space of Distributions

Definition 4.1
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\(\mathcal{D}(\Omega ) = C_c^\infty (\Omega )\) is the set of test functions together with a topology determined by its converging sequences : \(\phi _n \to \phi \) in \(\mathcal{D}(\Omega )\) if

  • there exists a compact subset \(K \subset \Omega \) such that \(\operatorname{Supp}(\phi _n) \subset K\).

  • For all multiindices \(\alpha \) we have \(\partial _\alpha \phi _n \to \partial _\alpha \phi \) in uniformly.

Convention: if \(x \in \mathbb {R}^d \setminus \Omega \), then \(\phi (x) := 0\).
\(\mathcal{D}'(\Omega )\) is the topological dual space, i.e. the space of continuous linear functionals \(D(\Omega ) \to \mathbb {C}\) with the weak-*-convergence, i.e. pointwise convergence.

Remark 4.2
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A notion of converging sequence on a set \(X\) is

  • The constant function on \(x\) converges to \(x\)

  • A sequence converges to \(x\) iff any subsequence has a subsequence converging to \(x\).

Note, that any subsequence of a converging sequence converges to the same limit. It induces a closure operator on \(X\) (for \(\overline{A \cup B} \subset \bar A \cup \bar B\) you use, that if a sequence in \(A \cup B\) converges to \(x\), then it has a subsequence (converging to \(x\)) lying in \(A\) or in \(B\)).

Example 4.3
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Every locally integrable function \(f \in L^1_{loc}(\Omega )\) gives us a distribution \(\Lambda f \in D'(\Omega )\) defined by

\[ \Lambda f (\phi ) = \int _{\Omega } f(x) \phi (x) \ \mathrm{d} x \]

which is well-defined because \(\phi \) has compact support.

Example 4.4

Let \(\mu \) be a Radon measure on \(\Omega \) (or more generally a signed Borel measure which is finite on compact subsets of \(\Omega \)). Then it defines a distribution:

\[ T_\mu (\phi ) = \int _{\Omega } \phi \ \mathrm{d} \mu \]
Proof ▶

As Borel sets are \(\mu \)-measurable, every continuous function is \(\mu \)-measurable. Let \(K := \operatorname{Supp}\phi \subset \Omega \). Because \(\mu (K) {\lt} \infty \) and \(\max \phi (K) {\lt} \infty \) it follows that \(\phi \) is \(\mu \)-integrable. Linearity follows from linearity of the integral. If \(\phi _j \to \phi _*\) unifomrly, then \(\operatorname{Supp}\phi _j \subset K\) for all \(j\) and \(T_\mu \phi _j \to \Lambda _\mu \phi _*\).

We have the following important special case:

Example 4.5 Dirac-\(\delta \)
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We have \(\delta \in D'(\Omega )\) given by

\[ \delta (\phi ) := \phi (0) \]

4.1.1 Convolution

Notation 1
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For \(\phi \in D\) define \(\phi ^R \in D\) as \(\phi ^R(x) = \phi (-x)\) and for \(x \in \mathbb {R}^d\) we have the shift \(\tau _x(\phi ) \in D\) given by \(\tau _x(\phi )(y) = \phi (y - x)\) .

Example 4.6
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For \(f \in L^1_{loc}(\Omega ), g \in D(\Omega )\) we have

\[ (f * g)(x) = \Lambda f (\tau _x (\psi ^R)) \]
Proposition 4.7

Let \(F \in \mathcal{D}'(\Omega ) , \psi \in D\). The following two distributions coincide:

  1. The distribution determined by the smooth function \(x \mapsto F(\tau _x (\psi ^R))\).

  2. The distribution \(\phi \mapsto F(\psi ^R * \phi )\).

We write this distribution as \(F * \psi \).

Proof ▶

\(\zeta := \psi ^R\) The function \(x \mapsto F(\tau _x(\psi ^R))\) is smooth :

  • It is continuous: If \(x_n \to x\), then \(\tau _x (\zeta ) - \tau _{x_n}(\zeta ) \to 0 \) uniformly and the same holds for partial derivatives. Now \(F\) is continuous hence \(F(\tau _{\bullet }(\psi ^R))\) is continuous and \(F\) preserves the difference quotients, hence it will be also smooth.

  • The two distributions coincide:

    \begin{align*} F(\psi ^R * \phi ) & = F \left(\int (\tau _x \psi ^R(\bullet ) \phi (x) \ \mathrm{d} x) \right) \\ & \overset {!}{=} \int F(\tau _x \psi ^R(\bullet ) \phi (x)) \ \mathrm{d} x \\ & = \int F(\tau _x \psi ^R) \phi (x) \ \mathrm{d} x \\ & = \Lambda (F(\tau _{\bullet } \psi ^R))(\phi ) \end{align*}

    Where we are allowed to pull out the integral by 4.8

Lemma 4.8

Let \(\phi \in C_c^{\infty }(\Omega \times \Omega )\). Then for any \(F \in D'(\Omega )\) we have

\[ F \left(\int _\Omega \phi (x,\_ ) \ \mathrm{d} x \right) = \int _\Omega F(\phi (x ,\_ )) \ \mathrm{d} x \]
Proof ▶

Consider \(S_\varepsilon \in D\) defined by

\[ S_\varepsilon ^\phi (y) = \varepsilon ^d \sum _{n \in \mathbb {Z}^d} \phi (n \varepsilon ,y) \]

which is a finite sum as \(\phi \) has compact support. Then for all \(\phi \in C_c^\infty (\Omega \times \Omega )\) one has a limit in \(\mathcal{D}\)

\[ \int _\Omega \phi (x,\_ ) \ \mathrm{d} x = \lim _{\varepsilon \to 0} S^\phi _\varepsilon \]

Hence by continuity of \(F\)

\begin{align*} F(\int _\Omega \phi (x,\_ ) \ \mathrm{d} x) & = F(\lim _{\varepsilon \to 0} S^\phi _\varepsilon ) \\ & = \lim _{\varepsilon \to 0} F(S^{\phi }_\varepsilon ) \\ & = \lim _{\varepsilon \to 0} \varepsilon ^d \sum _{n \in \mathbb {Z}^d} F(\phi (n \varepsilon ,\_ )) \\ & = \lim _{\varepsilon \to 0} S^{F \circ \phi }_\varepsilon \\ & = \int _\Omega F(\phi (x,\_ )) \ \mathrm{d} x \end{align*}

Using the first definition we learn the following two things

Example 4.9
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From the description 4.6: Writing \(\Lambda f * g\) is unambiguous.

Example 4.10
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We have \(\delta _0 * f = \Lambda f\) for all \(f \in D\).

Lemma 4.11

Convolution \(F * \psi \) is continuous in both variables.

Proof ▶

Continuity in the distribution variable is clear by pointwise convergence.
For the continuity in the test function variable one uses that convolution with a fixed test function is a continuous function \(\mathcal{D}\to \mathcal{D}\) and distributions are continuous.

Proposition 4.12

There exists a sequence \(\psi _n \in C_c^{\infty }(\Omega )\) such that \(\Lambda \psi _n \to \delta _0\) in \(D'(\Omega )\).

Proof ▶

Fix some \(\psi \in D\) with \(\int \psi (x) \ \mathrm{d} x = 1\). Define \(\psi _n (x) := n^d \psi (nx)\). Then

\[ (\Lambda \psi _n - \delta _0) (\phi ) = \int n^d \psi (n x) \phi (x) \ \mathrm{d} x - \phi (0) = \int \psi (x) \cdot (\phi (x / n) - \phi (0)) \ \mathrm{d} x \to 0 \]

where we used that \(\phi (x/n) - \phi (0) \to 0\) uniformly.

The following is how we view \(L^1_{loc}(\Omega ) \subset D'(\Omega )\).

Corollary 4.13

Let \(f,g \in L^1_{loc}(\Omega )\) such that \(\Lambda _f = \Lambda _g\). Then \(f = g\) almost everywhere.

Proof ▶

We have \(0 = \Lambda (f-g)(\tau _{\bullet } \psi _n^R) = \psi _n * (f - g) \to \delta _0 * (f-g) = f-g\) in \(L^1_{loc}\), hence \(f = g\) almost everywhere.

Example 4.14

\(\delta \) is not a function! I.e. its not of the form \(\Lambda f\) for some \(f \in L^1_{loc}\)

Proof ▶

We have \(\Delta |_{\Omega \setminus \{ 0\} }= \Lambda 0\) so if it would be a function, then it would be zero almost everywhere, hence 0. But this is a contradiction.

Corollary 4.15

Then \(C^\infty (\mathbb {R}^d)\) is dense in \(\mathcal{D}'(\mathbb {R}^d)\).

Proof ▶

We know by 4.12 that there exists \(\Lambda \psi _n \to \delta _0\) in \(\mathcal{D}'\). Let \(F\) be a distribution on \(\mathbb {R}^d\). Now setting \(F_n := F * \psi _n^R\) , yields pointwise

\[ F_n(\phi ) = F (\psi _n * \phi ) \to F(\delta _0 * \phi ) = F (\phi ) \]

by 4.11 hence \(F_n \to F\) in \(\mathcal{D}'\).

4.1.2 Derivatives

For \(\phi , \psi \in D\) we have

\[ \int _\Omega \partial ^\alpha \phi \psi \ \mathrm{d} x = (-1)^{|\alpha |} \int _\Omega \phi \partial ^\alpha \psi \ \mathrm{d} x \]

This motivates the definition

Definition 4.16
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For a multiindex \(\alpha \) and a distribution \(F\) define the distribution

\[ \partial ^\alpha F (\phi ) = (-1)^{|\alpha |}(F \partial ^\alpha \phi ) \]
Remark 4.17
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let \(f \in L^1_{loc}(\Omega )\). If there exists some \(f' \in L^1_{loc}(\Omega )\), such that \(\Lambda f' = \partial ^\alpha \Lambda f\) as distributions, then we call \(f'\) the weak derivative of \(f\) with respect to \(\alpha \).

Proposition 4.18

For \(F \in D', \phi \in D \) , We have

\[ \partial ^\alpha (F * \phi ) = (\partial ^\alpha F) * \phi = F * \partial ^\alpha \phi \]
Proof ▶

First note, that holds in the case where \(F\) is a test function, so that we have ordinary convolution. Then check pointwise. After erasing the sign \((-1)^{|\alpha |}\)

\[ F(\phi ^R * \partial ^\alpha \psi ) = F(\partial ^\alpha (\phi ^R * \psi )) = F((\partial ^\alpha \phi ) * \psi ) \]

4.1.3 Support

The Support of a distribution \(F\) is the complement of the largest open subset \(U\), such that \(F(\phi ) = 0 \forall \phi \in D, \operatorname{Supp}(\phi ) \subset U\). This definition is unambiguous: If \(F\) vanishes on each \(U_i\) for some index set \(I\) and \(\phi \in D\) such that the compact set \(\operatorname{Supp}\phi \subset U = \bigcup U_i\), we may assume that \(I\) is finite and choose a partition of unity \(\operatorname{Supp}\eta _i \subset U_i\) and \(\sum \eta _i = 1\). Then \(F(\phi ) = \sum F(\phi \eta _i) = 0\).

4.1.4 Tempered Distributions

We no enlarge our test space to the schwartz space \(\mathcal{S}= \mathcal{S}(\mathbb {R}^d)\) consisting of smooth functions that are rapidly decreasing at \(\infty \) with all derivatives.

Definition 4.19
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Consider the increasing sequence of norms on \(C^\infty (\Omega )\) defined by

\[ \| \phi \| _N = \sup \{ | x^\beta (\partial _x^\alpha \phi (x)) | \mid x \in \mathbb {R}^d , |\alpha |,\| \beta \| \le N\} \]
\[ \mathcal{S}= \{ \phi \in C^\infty (\mathbb {R}^d) \mid \| \phi \| _N {\lt} \infty \forall N\} \]

with the obvious notion of convergence.

Lemma 4.20
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We have a continuous inclusions \(\mathcal{D}\subset \mathcal{S}\), hence \(\mathcal{S}' \subset \mathcal{D}'(\mathbb {R}^d)\).
Moreover, this inclusion is dense. Hence being tempered is a property of distributions.

Lemma 4.21
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Let \(f \in L^1_{loc}(\mathbb {R}^d)\) such that there exists \(N \ge 0\) with

\[ \int _{|x| {\lt} R} |f(x)| \ \mathrm{d} x = O(R^N) , \text{ as } R \to \infty \]

The distribution \(\Lambda _f\) is tempered.

Example 4.22
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This condition holds for functions in \(L^p(\mathbb {R}^d)\) for \(p \in [1,\infty ]\)

Lemma 4.23
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If \(F \in \mathcal{D}'\) has compact support then it is tempered: Choose \(\eta \in \mathcal{D}\) such that \(\eta |_U = 1\) on some neighborhood \(U \supset \operatorname{Supp}(F)\). Then \(F(\eta \phi ) = F(\phi )\) for all \(\phi \in \mathcal{D}\) and \(\phi \mapsto F (\eta \phi )\) defines a continuous functional on \(\mathcal{S}\). It does not depend on the choice of \(\eta \), because given another such \(\eta '\) and any \(\phi \in \mathcal{S}\) we have \(\operatorname{Supp}((\eta - \eta ') \cdot \phi ) \cap \operatorname{Supp}(F) = \varnothing \).

Let \(F\) denote a tempered distribution.

Lemma 4.24
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  • All \(\partial ^\alpha F\) are tempered.

  • Let \(\psi \in C^\infty \) be slowly increasing, i.e. for each \(\alpha \) exists \(N_\alpha \) such that \(\partial _x^\alpha \psi (x) = O(|x|^{N_\alpha })\). Then \(\psi F\), defined by \((\psi F)(\phi )(F(\psi \phi )\) is tempered.

Example 4.25
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If \(\psi \in \mathcal{S}\), then \(F(\tau _\bullet (\psi ^R))\) is slowly increasing. The other formulation is still valid because \(\mathcal{S}\) is stable under \(*\).

What is the point of the Schwartz space?

Definition 4.26
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The fourier transformation is a continuous bijection

\begin{align*} \mathcal{S}& \to \mathcal{S}\\ \phi & \mapsto \hat\phi = (\xi \mapsto \int _{\mathbb {R}^d} \phi (x) e^{-2\pi i x \xi } \ \mathrm{d} x) \end{align*}
Lemma 4.27
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We have

\[ \Lambda _{\hat\psi }(\phi ) = \int _{\mathbb {R}^d} \hat\psi (x) \phi (x) \ \mathrm{d} x = \int _{\mathbb {R}^d} \psi (x) \hat\phi (x) \ \mathrm{d} x = \Lambda _{\psi }(\hat\phi ) \]

So its easy to define a compatible generalization to the tempered distributions:

Definition 4.28
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Define

\[ \hat F (\phi ) = F (\hat\phi ) \]

and similarly for the inverse transform \(f \mapsto \check{f}\).

We automatically have the inversion theorem for distributions, because it holds for test functions.

Example 4.29
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If \(1 \in S\) denotes the constant function at \(1\), then

\[ \widehat{\delta } = \Lambda _1 \]

because

\[ \hat\delta (\phi ) =\hat\phi (0) = \int 1 \phi (x) \ \mathrm{d} x = \Lambda _1(\phi ) \]

4.2 Fundamental solutions

In this chapter we may omit the \(\Lambda \). Fix a partial differential operator \(L\)

\[ L = \sum _{|\alpha |\le m } a_\alpha \partial ^\alpha \text{ on } \mathbb {R}^d \]

with \(a_\alpha \in \mathbb {C}\).

Definition 4.30
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A fundamental solution of \(L\) is a distribution \(F\) such that \(L(F) = \delta \)

The reason why this is interesting:

Lemma 4.31

The operator

\[ f \mapsto T(f) := F * f \]

defines an inverse to \(L\)

Proof ▶

because

\[ \partial ^\alpha (F * f) = (\partial ^\alpha F) * f = F * (\partial ^\alpha f) \]

Summing over \(\alpha \) gives

\[ L(F * f) = \delta * f = F * L f \]

Now recall \(\delta * f = f\).

Definition 4.32
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The characteristic polynomial of \(L\) is

\[ P(\xi ) = \sum _{|\alpha |\le m} a_\alpha (2 \pi i \xi )^\alpha \]

It is defined it such a way, that \(\widehat{L f} = P \cdot \hat f\). So our hope is

\[ F := \widecheck {1 / (P (\xi ))} = \int \frac{1}{P(\xi )} e^{2 \pi i x \xi } \ \mathrm{d} \xi \]

The problem is, that the zeros of \(P\) result in difficulties to define \(F\), even as a distribution.

4.2.1 Laplacian

If \(L = \Delta = \sum _{i=1}^d \frac{\partial ^2}{\partial ^2 x_i}\) So \(1 / P (\xi ) = 1 / (-4 \pi ^2 |\xi |^2) \) which lies in \(L^1_{loc}\) for \(d \ge 3\). To calculate our distribution the following is helpful

Theorem 4.33
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For \(\lambda {\gt} -d\), Let \(H_\lambda \) be the tempered distribution associated to \(|x|^\lambda \in L^1_{loc}\).
If \(-d {\lt} \lambda {\lt} 0\) then

\[ \widehat{H_\lambda } = c_\lambda H_{-d-\lambda } \]

with

\[ c_\lambda = \frac{\Gamma ((d + \lambda )/2)}{\Gamma (\lambda / 2)} \pi ^{-d/2-\lambda } \]

Set \(\lambda :=-d+2\). Hence we can find an appropriate constant \(C_d\) such that \(F(x) = C_d |x|^{-d +2}\) is a fundamental solution, because \(\hat{F}(\xi ) = 1 / (-4\pi ^2|\xi |^2)\). So writing out \(\widehat{\Delta F} = 1\).

Proposition 4.34

If \(d = 2\), the function \(F := 1/(2\pi ) \log |x| \in L^1_{loc}\) is a fundamental solution of \(\Delta \)

Proof ▶

Sketch. One can actually compute \(\hat F = -1 / (4\pi ^2) \left[\frac{1}{|x|^2} \right] - c' \delta \) for some constant \(c'\), where \(\left[\frac{1}{|x|^2} \right]\) is a distribution, that replaces the (non locally integrable) function \(1 / |x|^2\) in an appropriate way:

\[ \left[\frac{1}{|x|^2} \right] = \int _{|x| \le 1} \frac{\phi (x) - \phi (0)}{|x|^2} \ \mathrm{d} x + \int _{|x| {\gt} 1} \frac{\phi (x)}{|x|^2} \ \mathrm{d} x \]

Notice, that on the complement of zero, this distribution coincides with \(1 / |x|^2\).

Notation 2
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If \(\phi \in C^\infty (\Omega )\) slowly increasing (i.e. all derivatives are bounded by polynomials), define \(\phi F \in \mathcal{S}'\) as \(\phi F(\psi ) = F(\phi \psi )\).

\begin{align*} \widehat{ \Delta F} & = -4 \pi ^2 |x|^2 \hat F\\ & = |x|^2 \left[\frac{1}{|x|^2} \right] - 4\pi ^2 c’ \underbrace{|x|^2 \delta }_{=0} \\ & = 1 \end{align*}

4.2.2 Heat operator

\(L = \frac{\partial }{\partial t} - \Delta _x\) taken over \((x,t) \in \mathbb {R}^{d+1} = \mathbb {R}^d \times \mathbb {R}\) i.e. we want to solve the homogeneous initial value problem

\[ \begin{cases} L (u) = 0 & , t {\gt} 0 \\ u(x,0) = f(x) & , t = 0 \end{cases} \]

for some initial value \(f \in \mathcal{S}\).
We have

\[ (\frac{\partial }{\partial t} \hat{\mathcal{H}_t})(\xi ) = \widehat{\frac{\partial }{\partial t} \mathcal{H}_t}(\xi ) = \widehat{\Delta _x \mathcal{H}_t}(\xi ) = -4\pi ^2 |\xi |^2 \hat{\mathcal{H}_t} (\xi ) \]

and this is obviously solved by \(\mathcal{H}_t = e^{-4\pi ^2 |\xi |^2 t}\). We may call this the heat kernel

\[ \hat{\mathcal{H}_t}(\xi ) = e^{-4\pi ^2 |\xi |^2 t} \]

Note that for \(t = 0\), we have \(\hat{\mathcal{H}_0} = 1\), hence \(\mathcal{H}_0 = \delta \), so \(u(x,t) = (\mathcal{H}* f)(x)\) solves the equation \(L(u) = 0\) and \(u(x,t) \to f(x)\) in \(\mathcal{S}\) as \(t \to 0\).

Remark 4.35
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\(\mathcal{H}_t \to \delta \) in \(\mathcal{S}'\) as \(t \to 0\) and \(\int _{\mathbb {R}^d} \mathcal{H}_t(x) \ \mathrm{d} x = 1\) for all \(t\)

Now define

\[ F(x,t) := \begin{cases} \mathcal{H}_t(x) & , \ if \ t {\gt} 0 , \\ 0 & , t \le 0 \end{cases} \]

\(F\) is locally integrable on \(\mathbb {R}^{d+1}\) and it actually holds

\[ \int _{|t|\le R} \int _{\mathbb {R}^d} F(x,t) \ \mathrm{d} x \ \mathrm{d} t \le R \]

so \(F\) defines a tempered distribution by 4.21.

Theorem 4.36

\(F\) is a fundamental solution of \(L = \frac{\partial }{\partial t} - \Delta _x\).

Proof ▶

Denote \(L' = - \frac{\partial }{\partial t} - \Delta _x\), then we have to see the last equation

\[ LF (\phi ) = F(L'(\phi )) = \lim _{\varepsilon \to 0} \int _{t \ge \varepsilon } \int _{\mathbb {R}^d} F(x,t) ( -\frac{\partial }{\partial t} - \Delta _x) \phi (x,t) \ \mathrm{d} x \ \mathrm{d} t \overset {!}{=} \delta (\phi ) \]

Integration by parts

\begin{align*} & \int _{t \ge \varepsilon } \int _{\mathbb {R}^d} F(x,t) ( -\frac{\partial }{\partial t} - \Delta _x) \phi (x,t) \ \mathrm{d} x \ \mathrm{d} t \\ & = - \int _{\mathbb {R}^d} \left(\int _{t \ge \varepsilon } \mathcal{H}_t \frac{\partial }{\partial t} + (\Delta _x \mathcal{H}_t) \phi \ \mathrm{d} t \right) \ \mathrm{d} x \\ & = - \int _{\mathbb {R}^d} \left(\int _{t \ge \varepsilon } \mathcal{H}_t \frac{\partial }{\partial t} + ( \frac{\partial }{\partial t} \mathcal{H}_t) \phi \ \mathrm{d} t \right) \ \mathrm{d} x \\ & = \int _{\mathbb {R}^d} \mathcal{H}_\varepsilon (x) \phi (x,\varepsilon ) \ \mathrm{d} x & & \mid |\phi (x,\varepsilon ) - \phi (x,0)| \le O(\varepsilon ) \text{ uniformly in } x \\ & = \int _{\mathbb {R}^d} \mathcal{H}_\varepsilon (x) (\phi (x,0) + O(\varepsilon )) \ \mathrm{d} x & & \ref{remark:approxId}\\ & \to \phi (0,0) \end{align*}

where in the last line we let \(\varepsilon \to 0\)